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Forums >> Revit Building >> Technical Support >> Conditional toggle yes no formula
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Joined: Tue, Jul 15, 2008
16 Posts No Rating |
I am trying to control 3 visibility states but I only want one toggle on at a time. I know how to control 2 with a yes/no and a "not" condition, but I can't figure out how to control 3 yes/no so that only 1 is on at a time. Any help would be greatly appreciated.
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Joined: Wed, Aug 19, 2015
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I have done this before using a control integer value. When the integer value = 1 then the first item is visible, when it is = 2 then the second item is visible and so fourth. I would also add a text parameter that staes "Toggle visibility by cycling integer between 1 and 3".
the visibilty parameters would look something like this.
integer = 1 (this would turn item 1 on when the integer is 1)
integer = 2
integer = 3
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Joined: Tue, Jul 15, 2008
16 Posts No Rating |
That is similar to how I have had it set up, but it isn't the solution I am looking for. Trying to make this dummy proof. Thanks for the suggestion.
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Joined: Tue, Jul 15, 2008
16 Posts No Rating |
That is similar to how I have had it set up, but it isn't the solution I am looking for. Trying to make this dummy proof. Thanks for the suggestion.
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Joined: Wed, Aug 19, 2015
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As off current that is the simplest way to do it with just one control
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