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Forums >> Revit Building >> Technical Support >> Conditional toggle yes no formula

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Thu, Mar 3, 2016 at 8:03:12 AM | Conditional toggle yes no formula

#1

rgordon


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Joined: Tue, Jul 15, 2008
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I am trying to control 3 visibility states but I only want one toggle on at a time.  I know how to control 2 with a yes/no and a "not" condition, but I can't figure out how to control 3 yes/no so that only 1 is on at a time.  Any help would be greatly appreciated.


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Thu, Mar 3, 2016 at 8:49:22 AM | Conditional toggle yes no formula

#2

marmiketin1


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Joined: Wed, Aug 19, 2015
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4.5 Stars: 10 Votes


I have done this before using a control integer value. When the integer value = 1 then the first item is visible, when it is = 2 then the second item is visible and so fourth. I would also add a text parameter that staes "Toggle visibility by cycling integer between 1 and 3".

the visibilty parameters would look something like this.

integer = 1 (this would turn item 1 on when the integer is 1)

integer = 2

integer = 3


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Thu, Mar 3, 2016 at 9:14:55 AM | Conditional toggle yes no formula

#3

rgordon


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That is similar to how I have had it set up, but it isn't the solution I am looking for.  Trying to make this dummy proof.  Thanks for the suggestion.


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Thu, Mar 3, 2016 at 9:20:30 AM | Conditional toggle yes no formula

#4

rgordon


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That is similar to how I have had it set up, but it isn't the solution I am looking for.  Trying to make this dummy proof.  Thanks for the suggestion.


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Thu, Mar 3, 2016 at 11:43:05 AM | Conditional toggle yes no formula

#5

marmiketin1


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As off current that is the simplest way to do it with just one control


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