Forums >> Revit Building >> Technical Support >> Instance Parameter connected to a Visibility Parameter for Scheduling Purposes

macros976

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Joined: Wed, Mar 7, 2012
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A wall family may or may not have waterstop built in.  I have a visibility parameter for the waterstop and then I have

an instance parameter for the LF of the waterstop (should be the same as the LF of the wall).

If I turn the visibility parameter off for the waterstop, I don't want the length of waterstop to still show up in the schedule

since it won't be there for that wall.

I tried meddling with some conditioned statements, but couldn't get them to not be circular.

Viz Parameter = Waterstop

Length Parameter = Waterstop LF

I tried this in the Length Parameter box: IF(Waterstop =0,0,Waterstop LF)  - got a circular logic warning, but I don't know

how else to refer back to its value when there is waterstop present.

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TKennedy

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Joined: Wed, Oct 7, 2009
654 Posts

Yes/No parameters are a little funny when it comes to formulas, and you can't tell a parameter to read itself (this is where you are getting the circular reference error). Try this:

Waterstop = Y/N parameter

Waterstop LF 1 = User adjusted length parameter

Waterstop LF 2 = The parameter read by the schedule

Formula for Waterstop LF 2 = if(not(Waterstop), 0' - 0", Waterstop LF 1)

You may be able to make Waterstop LF 2 a calculated value in your schedule, and make the Waterstop LF 1 column hidden.

Also, because Revit seems to have to put a value in Length parameter cells, I don't think you're going to be able to make it display nothing if the value is 0. It's going to display 0' - 0".

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