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Forums >> Revit Building >> Technical Support >> Visibility parameter
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Joined: Wed, Apr 9, 2008
4 Posts
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Hi Basically I have an extrution in a family which only should be visible if a length (Height1) is from 800mm to 1200mm. I want to control this with a Yes/No parameter, but I can't figure out to how to write the correct formula. Is there any way to tell the extrution to be "yes" if (>1200 and <800)? /thanks
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Joined: Thu, Oct 7, 2010
64 Posts
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There is probably a better way but see the attached image for something that worked for me. Set up these parameters then click on your extrusion and set is visibility to link to the 'Extrusion Visibility' Parameter. The Visibility YES & Visibility NO are just dummy operators that shouldn't be touched.
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Joined: Tue, May 16, 2006
13079 Posts
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Try a nested if....
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Joined: Wed, Oct 7, 2009
654 Posts
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Yes/No parameters are a little weird, they seem to assume the 'if' and therefore don't need it in the formula. Try something like 'and((Height1 > 800mm), (Height1 < 1200mm))'. If that condition is true the Yes/No parameter is checked, if false, unchecked.
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Joined: Wed, Apr 9, 2008
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Hey Thanks for all the help.. I made it work with the: "and(Height1 < 1200 mm, Height1 > 800 mm)"But thanks alot for the input.
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